Re: accessing variable vaule outside for loop

How about something like this:

#!/usr/bin/perl

use strict;

my @number;
my @rev;
@number = (1,2,3,4);
my $index1 = @number;
my $revIndex = 0;
my $x = 0;
for ($x= 0; $x < $index1 ; $x+= 1)
    { 
        
        $revIndex = $index1 - $x;
        $rev[$revIndex] = $number[$x];
        
#case1#
 print "@rev \n" ;
}
#case2# 
print "@rev \n";
[download]

Michael

Comment on Re: accessing variable vaule outside for loop Download Code

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Re^2: accessing variable vaule outside for loop by gaurav (Sexton) on Jul 06, 2013 at 12:48 UTC
Hi Michael,but its output is some type of pyramid means,when I ran your code I got `1 2 1 3 2 1 4 3 2 1 4 3 2 1` [download] But I need reverse of it,anyway thanks for it	[reply] [d/l]
Re^3: accessing variable vaule outside for loop by Laurent_R (Canon) on Jul 06, 2013 at 14:38 UTC
Just remove the print statement inside the for loop, and you will no longer get this "pyramid". I think this print statement was put there just to show you how the array get progressively populated.	[reply]
Re^3: accessing variable vaule outside for loop by gaurav (Sexton) on Jul 06, 2013 at 14:57 UTC
Thanks Michael,Its working fine	[reply]
Re^4: accessing variable vaule outside for loop by mtmcc (Hermit) on Jul 06, 2013 at 19:39 UTC
glad to help.	[reply]