Re: giving spaces

If the regex does not have an x modifier, just use a literal space. If it does have an x modifier, put the space into a character class:

13:26 >perl -wE "my $s = 'a b'; say 'matched' if $s =~ /a b/;"
matched

14:47 >perl -wE "my $s = 'a b'; say 'matched' if $s =~ /a[ ]b/x;"
matched

14:47 >
[download]

Hope that helps,

Athanasius <°(((>< contra mundum Iustus alius egestas vitae, eros Piratica,

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Re^2: giving spaces by Anonymous Monk on Jul 17, 2013 at 04:54 UTC
say I have two arrays , arrayA and arrayB . and I wish to print something like this `print " \s $arrayA[$i] \s $arrayB[$i] \s";` [download] I have assumed that \s is giving space , so I just want , what should i replace $s with ?	[reply] [d/l]
Re^3: giving spaces by mtmcc (Hermit) on Jul 17, 2013 at 07:46 UTC
If that's what you want to print, you don't need any space regex. `print " $arrayA[$x] $arrayB[$x] ";` will print the spaces too... I hope that helps. -Michael	[reply] [d/l]
Re^3: giving spaces by Anonymous Monk on Jul 17, 2013 at 05:25 UTC
`$var1." ".$var2;`	[reply] [d/l]
Re^3: giving spaces by BillKSmith (Monsignor) on Jul 17, 2013 at 14:09 UTC
If you use `use strict; use warnings;` you will probably find an error in this statement that has nothing to do with spaces. I suspect that you intend $i to be a subscript. If so, `print " $arrayA[$i] $arrayB[$i] ";` [download] Note: \s is special character class for regular expressions. It does not have the same meaning in a string. Just use space characters. Bill	[reply] [d/l] [select]