in reply to remove spaces after join operation

Not sure this is exactly what you're looking for, but: 
print join(' ',@first_sentence) =~ s/\s*([.()])\s*/$1/gr;

[download]
Prints: 
i am 2(but).how

[download]

Replies are listed 'Best First'.
Re^2: remove spaces after join operation
by lakssreedhar (Acolyte) on Jul 26, 2013 at 11:27 UTC

    This error Can't modify join or string in substitution (s///) at out.pl line 5, near "s/\s*(\.\(\))\s*/$1/g;" is being shown

[reply]
      Ah, is your version of Perl too old to support the /r modifier? It wont work without it. I Suppose: 
      my $txt = join ' ',@first_sentence;
$txt =~ s/\s*([.()])\s*/$1/g;
print $txt;

      [download]
      Updated to simplify regex as suggested by hdb
[reply]
[d/l]

        ya its working now

[reply]

In Section Seekers of Perl Wisdom