in reply to In-place bitwise NOT?

Probably not fast enough: 
$bits =~ s/(.)/~$1/ges;

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Re^2: In-place bitwise NOT? (tr)
by tye (Sage) on Jul 26, 2013 at 17:36 UTC
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[d/l]

      Nice. Thank you.

      With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
      Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
      "Science is about questioning the status quo. Questioning authority".
      In the absence of evidence, opinion is indistinguishable from prejudice.
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Re^2: In-place bitwise NOT?
by BrowserUk (Patriarch) on Jul 26, 2013 at 17:41 UTC

    No. I'm dealing with multi-gigabyte bitstrings.

    With the rise and rise of 'Social' network sites: 'Computers are making people easier to use everyday'
    Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
    "Science is about questioning the status quo. Questioning authority".
    In the absence of evidence, opinion is indistinguishable from prejudice.
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