Re: Wordfeud racks

How many tiles are in the bag?

for example, if it's only 100 then you're going to have to create 80,678,106,432,000 unique combinations - which might take a while :)

Comment on Re: Wordfeud racks

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Re^2: Wordfeud racks by choroba (Cardinal) on Jul 30, 2013 at 17:02 UTC
How did you get the number? Combinations `$ echo $(echo {2..100} \| sed 's/ /*/g') \ / $(echo {2..7} \| sed 's= =/=g') \ / $(echo {2..93} \| sed 's= =/=g') \| bc 16007560800` [download] Also confirmed at http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html and http://easycalculation.com/statistics/permutation-combination.php. لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l]
Re^3: Wordfeud racks by RichardK (Parson) on Jul 30, 2013 at 17:29 UTC
Sorry, I meant permutations, so there a N!/(N-K)! ways to select K tiles from a bag of N. Or for 7 of 100 tiles = 100999897969594 permutations. I think it will be easier to calculate the probabilities of the different combinations rather than count them, but it's still going to be a fair amount of work.	[reply]