Re^3: AM/PM to 24 hours

This is my first time on the post so :

ID,21,11814,1,11989,150,Y,10/25/2012 11:36:25 AM,TEST 

"ID",22,11814,1,11989,150,Y,10-25-2012 11:36:25 PM,TEST
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I need to change the time stamp and make the lines look like this . how can I convert this to this using a perl one liner ?

ID,21,11814,1,11989,150,Y,2012-10-25-11.36.25.0000, TEST 

ID,22,11814,1,11989,150,Y,2012-10-25-23.36.25.0000, TEST
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Re^4: AM/PM to 24 hours by Loops (Curate) on Aug 05, 2013 at 19:49 UTC
I took up the challenge to do this as a perl one liner, but this version is much easier to understand and build on in the future: `use Date::Manip; use Text::CSV; my $csv = Text::CSV->new; while (<>) { $csv->parse($_); my @f = $csv->fields; $f[7] = UnixDate $f[7], "%Y-%m-%d-%H.%M.%S.0000"; $csv->combine(@f); print $csv->string . "\n"; }` [download] Output: `ID,21,11814,1,11989,150,Y,2012-10-25-23.36.25.0000,TEST ID,22,11814,1,11989,150,Y,2012-10-25-23.36.25.0000,TEST` [download] * Should note that the example above isn't kosher as per the documentation. It will fail on embedded newlines and isn't Unicode friendly. Best to consult that documentation if this is anything other than a one-off.	[reply] [d/l] [select]
Re^4: AM/PM to 24 hours by toolic (Bishop) on Aug 05, 2013 at 19:29 UTC
perlintro QandASection: dates and times	[reply]
Re^4: AM/PM to 24 hours by 0day (Sexton) on Aug 05, 2013 at 20:29 UTC
Here is a simple regular expression to convert a string `while (<DATA>) { s/(\d+)\/(\d+)\/(\d+)\s+(\d+):(\d+):(\d+)\s+(PM\|AM)/$3.'-'.$1.'-'. +$2.'-'.($7 eq 'PM'?($4+12):$4).'.'.$5.'.'.$6.'.0000'/ge; print $_; } __DATA__ ID,21,11814,1,11989,150,Y,10/25/2012 11:36:25 AM,TEST ID,22,11814,1,11989,150,Y,10/25/2012 11:36:25 PM,TEST` [download] Output: ID,21,11814,1,11989,150,Y,2012-10-25-11.36.25.0000,TEST ID,22,11814,1,11989,150,Y,2012-10-25-23.36.25.0000,TEST	[reply] [d/l]