in reply to phi div by 0 error

A faster way is to use $phi = (1+sqrt(5))/2;

However, if you insist of using the ratios of Fibonacci numbers (it would have been nice to mention that), then you need to create 20 of them (rather than 10) if you always divide the even numbered ones by the odd numbered ones. So let your first loop run until 20 instead of 10.

UPDATE: A postfix loop solution for you:

use strict;
use warnings;

my @list = ( 1, 1 );
push @list, $list[-1]+$list[-2] for 0..17;
print +($list[2*$_+1] / $list[2*$_]) . "\n" for 0..9;

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Re^2: phi div by 0 error
by perlaintdead (Scribe) on Sep 01, 2013 at 14:29 UTC

    thanks. I actually solved this one before saw your post on a hunch because i saw it outputed exactly half of what i was expecting. I'll have to play around with that sqrt trick.

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Re^2: phi div by 0 error
by perlaintdead (Scribe) on Sep 01, 2013 at 14:34 UTC

    (1+sqrt(5))/2 came out to 3.23606797749979 AKA not phi

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      just needed another parentheses ((sqrt(5)+1)/2)

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        or a small re-order

        perl -le ' print ( (1 + sqrt 5) / 2 )'

        Cheers,
        R.

        Pereant, qui ante nos nostra dixerunt!
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