Re^4: $_ functions vs argument-using functions

Yeah. These magic parsing exceptions are clearly not accessible to normal users, especially since the perldoc page doesn't seem to document it at all. How was I supposed to find out about this exception reading the docs?

In any case, I cannot include a large amount of code in an anonymous block passed to map(). So I guess this sanctions the use of $_-using functions.

Comment on Re^4: $_ functions vs argument-using functions

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Re^5: $_ functions vs argument-using functions by LanX (Saint) on Sep 09, 2013 at 19:31 UTC
It's documented, see perlglossary for "expression". The point is you can't reuse this coding style very often, so better avoid it. You can write `sub func (&@) { }` to use block syntax. like in `func {shift()+1 } 1..10` Or you can directly pass function references `f(\&g(\&h),1..10)` or anonymous subs `f(sub {...},1..10)` without using prototypes at all. But Perl won't allow you to rewrite anything like `func EXPR, LIST` acting like `map` does. And as I said have a look into HOP. Please understand that I won't go further into details of a theoretical discussion, I'd rather prefer to see a real use case from you such that we can recommend the Perl way to do it. Cheers Rolf ( addicted to the Perl Programming Language)	[reply] [d/l] [select]

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Re^5: $_ functions vs argument-using functions
by LanX (Saint) on Sep 09, 2013 at 19:31 UTC

perlglossary

The point is you can't reuse this coding style very often, so better avoid it.

You can write sub func (&@) { } to use block syntax. like in func {shift()+1 } 1..10

Or you can directly pass function references f(\&g(\&h),1..10)

or anonymous subs f(sub {...},1..10)

without using prototypes at all.

But Perl won't allow you to rewrite anything like func EXPR, LIST acting like map does.

And as I said have a look into HOP.

Please understand that I won't go further into details of a theoretical discussion, I'd rather prefer to see a real use case from you such that we can recommend the Perl way to do it.

Cheers Rolf

( addicted to the Perl Programming Language)

[reply]
[d/l]
[select]