in reply to extract file name from path

We can probably assume the pattern will always start with a / (since that's part of the path) and end with some sort of .ext: 
my $line = 'root 30145 1 0 Jan30 ? 00:09:01 /root/java/app/java_app_1R
+ule_java_app_2Rule.java --javaproc';

if ($line =~ m|/([^/]*?)\.[a-z0-9]+|) {
    print "$1\n";
}

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Re^2: extract file name from path
by Laurent_R (Canon) on Sep 12, 2013 at 07:52 UTC

    I think that you need to add the underscore ('_') to the character class in your regex.

    Update: I read too quickly. Reading again your regex, no, there is no need to add the underscore, since this character class is aimed at matching the final "java" extension.

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