in reply to question 1st - undefined behaviour

I think the first and second $x would be 6 actually, due to the prepend happening on the second $x.

Here are the steps in order:

1. ++$x: All $x are now 6.

2. 6 + 6 + 6

3. $x++: All $x are now 7.

4. $x = 18: The value from the 6 + 6 + 6 is assigned to $x.

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Re^2: question 1st - undefined behaviour
by rumos2 (Acolyte) on Sep 23, 2013 at 22:21 UTC
    sorry if I making a mistake, but looks like you are wrong - why - try understand why
    my $x=5;
$x=++$x + $x++ + $x;
warn $x;

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    return's 20.
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[d/l]
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