in reply to Re^5: Challenge: 8 Letters, Most Wordsin thread Challenge: 8 Letters, Most Words
Cheers - L~R
Anyway you don't need to check against all words in the dictionary, only taking the (at most) 256 subsets of a potential 8 letter combination. (less if letters are repeated)
This can be done in a lookup in a prepared count-hash with normalized keys.
Cheers Rolf
( addicted to the Perl Programming Language)