in reply to Re^6: Creating 'new' subroutine.
in thread Creating 'new' subroutine.
You posted code where you test an array with ref, it doesn't do what you think it does (it does nothing)
its the equivalent of if( not ref "shamalama" eq "dingdong" ){ ... }
its equivalent to if(1){ ... }
clear now?
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Re^8: Creating 'new' subroutine.
by Lennotoecom (Pilgrim) on Oct 11, 2013 at 11:48 UTC | |
by Anonymous Monk on Oct 11, 2013 at 12:00 UTC | |
by Lennotoecom (Pilgrim) on Oct 11, 2013 at 12:04 UTC |