in reply to Re^2: In place replace, ignoring between quotes
in thread In place replace, ignoring between quotes

If $var is true, then !$var is false ('').
If $var is false, then !$var is true (1).

That new value is then assigned to $var

Alternatively, you could say $var ^= 1 to do the same sort of thing, just with 1 and 0 instead of 1 and ''.

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Re^4: In place replace, ignoring between quotes
by trippledubs (Deacon) on Oct 25, 2013 at 19:47 UTC

    Nice. ^=1 makes more sense to me.

    I guess I have a hard time understanding because if $var = 0 (or "") then you say $var = ! $var, why 1? Why not, 50? I mean practically speaking it works and that is what is important. I guess it doesn't have to exactly translate to English. Thanks for sharing!
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