in reply to In place replace, ignoring between quotes
Look-ahead for even number of quotes:
$_ = q[cd / ; /path/to/R/R_latest --vanilla --args "fName='rGSDPlan';j +obCode=682718;jobId=6827181;" < job682718.R > job_6827181.txt]; say s/;(?=[^"]*(?:"[^"]*"[^"]*)*$)/&&/gr;
Output:
cd / && /path/to/R/R_latest --vanilla --args "fName='rGSDPlan';jobCode +=682718;jo bId=6827181;" < job682718.R > job_6827181.txt
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