From perlvar:

$-[0] is the offset of the start of the last successful match.

You have my $re1 = qr/((a+)?(b+)?(c))*/;

Your outer capture group may be repeated zero or more times. In the case of your test string, "aacbbbcac", it matches three times:

At the first repeat, it matches "aac" with $1 being "aac", $2 being "aa", $3 being undef (not matched) and $4 being "c", but because of the repeat count it doesn't stop there, so you never see these values.

At the second repeat $1 is "bbbc", $2 remains "aa" (group (a+) didn't match in this repeat but $2 is the 'last successful match'), $3 is "bbb" and $4 is "c", but it doesn't stop there, so you don't see these values either.

The third and final repeat sets $1 to "ac", $2 to "a" leaves $3 as it was at the last successful match (i.e. "bbb") and sets $4 to "c".

So, the issue is that the capture groups return the last successful match rather than the last match or failure as the case may be.

Thank you very much. So I cannot get individuals without removing the repetition and do a while ()... i.e.

use strict;
use warnings FATAL => 'all';
 
my $string = "aacbbbcac";
 
my $re1 = qr/((a+)?(b+)?(c))/;
while ($string =~ /$re1/g) {
  foreach (0..$#-) {
    printf "Group %d: <%s>\n", $_, defined($-[$_]) ? substr($string, $
+-[$_], $+[$_] - $-[$_]) : '';
  }
  print "\n";
}
[download]

Bad news for me, but again mega thanks for your very clear answer. ps:

Group 0: <aac>
Group 1: <aac>
Group 2: <aa>
Group 3: <>
Group 4: <c>

Group 0: <bbbc>
Group 1: <bbbc>
Group 2: <>
Group 3: <bbb>
Group 4: <c>

Group 0: <ac>
Group 1: <ac>
Group 2: <a>
Group 3: <>
Group 4: <c>
[download]