How can i call the subroutine of the shell script and pass certain parameters to it?

mkp19901 has asked for the wisdom of the Perl Monks concerning the following question:

#!/usr/bin/perl
### need something like this
source file.sh
routine;           
 # <-- this is supposed to be part of file.sh which is called 
                   
 # from perl script and some parameter are passed to it
[download]

Comment on How can i call the subroutine of the shell script and pass certain parameters to it? Download Code

Replies are listed 'Best First'.
Re: How can i call the subroutine of the shell script and pass certain parameters to it? by hippo (Archbishop) on Oct 29, 2013 at 13:20 UTC
Did you try this: `system ('. file.sh && routine');` It's untested, but may give you a pointer. However, I advise against the whole principle as it will be somewhat lacking in transparency and therefore maintainability. YMMV. It does sound a little like an XY Problem.	[reply] [d/l]
Re: How can i call the subroutine of the shell script and pass certain parameters to it? by Anonymous Monk on Oct 29, 2013 at 13:19 UTC
Can't be done, perl isn't shell. see system, qx, perlipc	[reply]
Re^2: How can i call the subroutine of the shell script and pass certain parameters to it? by Corion (Patriarch) on Oct 29, 2013 at 13:26 UTC
Also see do, which would be the closest thing to `source` in terms of Perl. Or maybe Get default login environment, if the objective is "just" to set up some environment. Still, defining and then calling shell functions from within Perl requires lots of effort that I'd try to avoid.	[reply] [d/l]
Re: How can i call the subroutine of the shell script and pass certain parameters to it? by builat (Monk) on Oct 29, 2013 at 17:04 UTC
If you have some *.sh script with some kind of output good way to do my $ScalarForOutput = `sh MyScript.sh`; following this way you take output of MyScript.sh in `$ScalarForOutput`	[reply] [d/l] [select]