Re: Dereferencing array of hashes

Also note that it's not necessary to use a C-style loop...

Yes, sure, but you don't even need a $i variable to loop on the array and make a real Perl loop using directly the reference. This makes the dereferencing simpler.

use strict;
use warnings;

my @AoH = (
    {
        a => "a1",
        b => "b1",
        c => "c1",
    },
    {
        d => "d1",
        e => "e1",
        f => "f1",
    },

    {
        g => "g1",
        h => "h1",
        i => "i1",
    },
);

for my $hashref (@AoH) {
    print "$_ => $$hashref{$_}\n" for (keys %$hashref);
}
[download]

which will print:

$ perl  aoh.pl
c => c1
a => a1
b => b1
e => e1
d => d1
f => f1
h => h1
g => g1
i => i1
[download]

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Re^2: Dereferencing array of hashes by AnomalousMonk (Archbishop) on Nov 11, 2013 at 20:17 UTC
monkini: The critical thing to remember here is that a so-called "array of hashes" (an `@AoH`) is actually an array of hash references, i.e., every element is already a hash reference. You may as well use those references as such in a Perl-style `for`-loop as shown by Laurent_R (although I would have used the arrow de-referencing notation `$hashref->{$_}` instead of the `$$hashref{$_}` form).	[reply] [d/l] [select]
Re^3: Dereferencing array of hashes by Laurent_R (Canon) on Nov 11, 2013 at 22:50 UTC
(although I would have used the arrow de-referencing notation $hashref->{$_} instead of the $$hashref{$_} form) Yes, right, that's actually what I would probably do also given the time. I typed my post in a rush before leaving for something else and used the dereferencing notation I still know best, but I have been trying in the last months to use more and more the arrow dereferencing notation, which is somewhat clearer. I am now using systematically the arrow notation for code refs and am trying to do it more and more for hash or array refs.	[reply]