@{$ref}{@head} = @aa;
[download]

...is a hash slice, similar to @hash{@keys} = @values, except that in the former case, $ref holds a hash-ref, whereas in the latter case, %hash holds a plain hash.

I might not have expressed myself correctly, but I was only trying to say that, since $ref and @head are never changing in the presented code, each time through the loop, the values of @aa will clobber the previously recorded ones, so that the loop is in effect useless, it would be faster to go straight to the last line of the file, split it and run the discussed command only once. Example under the Perl debugger:

  DB<1>  @head = qw 'foo bar baz'

  DB<2>  @{$ref}{@head} = qw /one two three/;

  DB<3> x $ref
0  HASH(0x8032f9b8)
   'bar' => 'two'
   'baz' => 'three'
   'foo' => 'one'
  DB<4>  @{$ref}{@head} = qw /four five six/;

  DB<5> x $ref
0  HASH(0x8032f9b8)
   'bar' => 'five'
   'baz' => 'six'
   'foo' => 'four'
  DB<6>
[download]

The assignment of line 4 is clobbering what was previously in the hash referenced by $ref. It does not make sense to do that in a loop, since only the last assignment of the loop is useful.

Or the real code is different, in which case it might be useful to see the real code.

so that the loop is in effect useless, it would be faster to go straight to the last line of the file, split it and run the discussed command only once.

What "discussed command"? The OP doesn't mention any command; nor show any "command".

You appear to be assuming that the op reads all the lines of the file; and then runs this "discussed command" once the rad loop ends; but there is no evidence of that within the thread.

An alternative scenario: He reads a line; splits it to the hash; accesses a few named fields and performs some calculation that affects some variables declared before the loop is entered; and then loops back and reads the next line; until the file is read.

There is no evidence from the OP one way or the other anywhere in the thread, but to assume your version is to assume the OP is ...

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