in reply to Re^2: sort +*, @array
in thread sort +*, @array

Thanks for your reply.

So it is the Perl 6 equivalent to say sort {$a <=> $b} @array;?

But how is that statement related to the Schwartzian transformation?

Replies are listed 'Best First'.
Re^4: sort +*, @array
by raiph (Deacon) on Dec 09, 2013 at 13:53 UTC
    The +* is a "key extractor" closure. This closure corresponds to the before map of the ST. Of course, in the specific case of +*, it's trivial to instead just specify a "comparator" closure using <=>, but what if one instead writes: 

    say sort +*.value, 1=>4,  11=>5,  2=>99,  22=>22,  3=>339
# prints           1=>4   11=>5   22=>22  2=>99    3=>339

say sort ~*.value, 1=>4,   11=>5,  2=>99,  22=>22,  3=>339
# prints           22=>22  3=>339  1=>4    11=>5    2=>99

    [download]

    (And of course the results of the closure call on a given item is memoized.)

    »ö« . o O ( "the celebrity tell-all of the Perl-6 cult?" )

[reply]
[d/l]
[select]

      Thanks for the explanation. So the link to the Schwartzian really is the fact that the items are automatically memoized.

[reply]

In Section Meditations