Re: How does one get all possible matches from regex?

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Re^2: How does one get all possible matches from regex? by LanX (Saint) on Dec 10, 2013 at 03:38 UTC
I didnt understand the OP, but is this not easier? `print $1 while /(REGEX)/g` Cheers Rolf ( addicted to the Perl Programming Language)	[reply] [d/l]
Re^3: How does one get all possible matches from regex? by educated_foo (Vicar) on Dec 10, 2013 at 04:17 UTC
They're different: `/X/g` does non-overlapping matches; `/X(?{print$&})(?!)/` does all matches. It depends what you want.	[reply] [d/l] [select]
Re^4: How does one get all possible matches from regex? by LanX (Saint) on Dec 10, 2013 at 16:27 UTC
Well it took me a while to understand whats going on in your code... Please note that the while-loop is redundant (and confusing =) `DB<138> $_=" x1x2x3x x4x5x" => " x1x2x3x x4x5x" DB<139> ; /x(\d)x(?{print "<$1>\t"})(?!)/ <1> <2> <3> <4> <5>` [download] by placing an _empty_ negative lookahead you are forcing your regex to reject all matches and to backtrack through the whole string. But the embedded perlcode (which is an experimental feature IIRC) prints the temporary match before the next attempt is started. edit as a side note, the same effect can be achieved with "conventional" means (i.e. manipulation of pos) `DB<154> while ( /x(\d)x/g ) { print $1; pos($_) -= length($ &)-1 } 12345` [download]	[reply] [d/l] [select]