DB<125> @a=(0)x10
 => (0, 0, 0, 0, 0, 0, 0, 0, 0, 0)

  DB<126> sub any (&@) { 
           my $cr=shift; 
           defined first { &$cr } @_ 
           }

  DB<127> any {$_==0} @a
 => 1
[download]

well could be faster if I could avoid '$cr' but my golfing foo is weak today. =)

update

got it :)

  DB<138> sub any (&@) { defined &first (shift, @_) } 

  DB<139> any {$_==0} @a
 => 1
[download]

update

better :)

  DB<144> sub any (&\@) { defined &first } 

  DB<145> any {$_==0} @a
 => 1
[download]

UPDATE

DARN! still buggy with false positives!

didn't sleep enough...

update

this seems to work...

  DB<230> sub any (&@) {  my $x=&List::Util::first; defined $x  } 

  DB<231>  any { $_ eq 0 } @a
 => ""

  DB<232>  any { $_ eq 5 } @a
 => 1

  DB<233> @a
 => (1, 2, 3, 4, 5)
[download]

Works fine until you want to see if an array contains any false values...

use Data::Dumper;
use List::Util ();

sub any (&@) { my $x = &List::Util::first; defined $x }

my @x = (1..3, undef, 5..10);  # undef is false
print Dumper(any { !$_ } @a);
[download]

use Moops; class Cow :rw { has name => (default => 'Ermintrude') }; say Cow->new->name

Thanks, but this can't be fixed.

The problem is that the design of List::Util first is broken, no result should be an empty list and not undef! At least in list context ! :(

  DB<28> \@x
 => [1, 2, 3, undef, 5, 6, 7, 8, 9, 10]

  DB<29> @a=List::Util::first { !$_ } @x; \@a
 => [undef]

  DB<30> @a=List::Util::first { $_ eq "never" } @x; \@a
 => [undef]
[download]

I wished people would learn the lesson that () is always better then undef for failure in list operations like iterators or filters.

update

grep does it right!

  DB<38> @a=grep { !$_ } @x; \@a
 => [undef]

  DB<39> @a=grep { $_ eq "never" } @x; \@a
 => []
[download]

Cheers Rolf

( addicted to the Perl Programming Language)

hmm maybe simpler than we thought!

  DB<25> sub first (&@) { my $code=shift; grep {return $_ if &$code} @
+_ }

  DB<26> first { $_ >5 } 1..10
 => 6

  DB<27> first { $_ >10 } 1..10

  DB<28> sub any (&@) { my $code=shift; grep {return 1 if &$code} @_ ;
+ ()}

  DB<29> any { $_ >10 } 1..10
 => ""

  DB<30> any { $_ >5 } 1..10
 => 1
[download]

Can you spot problems?

update

variation of first for finding position

  DB<40> sub position (&@) { my $code=shift; my $idx=-1; grep {++$idx;
+ return $idx if &$code} @_ ; ()}

  DB<41> position { !$_ } 1..10,undef,11..20
 => 10
[download]

update

changed "" to () for false.

update

even easier

  DB<53> sub first (&@) { my $code=shift; &$code and return $_ for @_ 
+; ()}

  DB<54> sub any (&@) { my $code=shift; &$code and return 1 for @_ ; (
+)}
[download]

Cheers Rolf

( addicted to the Perl Programming Language)