Re^2: Perl RE; how to capture, and replace based on a block?

Um. I did that;
Code to replace

</div>
</body>
[download]

RE I'm using, that doesn't work

\<\/div\>\n\<\/body\>
[download]

As stated in my OP; my RE (shown) matches one, or the other, not both. I had hoped to match both (</div></body>). Is it clearer?

--Chris

Yes. What say about me, is true.

Comment on Re^2: Perl RE; how to capture, and replace based on a block? Select or Download Code

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Re^3: Perl RE; how to capture, and replace based on a block? by Anonymous Monk on Dec 18, 2013 at 00:30 UTC
Um. I did that; Sorry but you didn't. You posted some data and a pattern you say you want to match the data but it doesn't match -- great, now show your code that uses the pattern with this data that fails to match it works "perfectly" as expected `Compiling REx "\<\/div\>\n\<\/body\>" Final program: 1: EXACT <</div>\n</body>> (6) 6: END (0) anchored "</div>%n</body>" at 0 (checking anchored isall) minlen 14 Guessing start of match in sv for REx "\<\/div\>\n\<\/body\>" against +"</div>%n</body>" Found anchored substr "</div>%n</body>" at offset 0... Guessed: match at offset 0 Freeing REx: "\<\/div\>\n\<\/body\>"` [download]	[reply] [d/l]
Re^4: Perl RE; how to capture, and replace based on a block? by taint (Chaplain) on Dec 18, 2013 at 01:22 UTC
OK. To be more concise; I used cat to feed the file to Perl using an inline regex. Yes. What say about me, is true.	[reply]
Re^5: Perl RE; how to capture, and replace based on a block? by AnomalousMonk (Archbishop) on Dec 18, 2013 at 01:42 UTC
That's concise, but I have no idea what it means.	[reply]
Re^5: Perl RE; how to capture, and replace based on a block? by Anonymous Monk on Dec 18, 2013 at 02:18 UTC
OK. To be more concise; I used cat to feed the file to Perl using an inline regex. And then what happened? How is that a program that shows the problem, a program I can run on my computer through copy/paste?	[reply]