Re: how to select which words have Y and W

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Re^2: how to select which words have Y and W by LanX (Saint) on Dec 26, 2013 at 12:15 UTC
yes it's possible `DB<114> @a=(12,-85,36,-10,75,-38) => (12, -85, 36, -10, 75, -38) DB<115> @a = grep { $_ >= 0 } @a => (12, 36, 75)` [download] But for the basics people here appreciate if you first read docs (or a Perl book) and try the examples there before asking. People already provided links (like here) and they would like to get feedback if those links helped (and if not, why, to be able to improve them) Thats the way we help to learn efficiently! :-) Cheers Rolf ( addicted to the Perl Programming Language)	[reply] [d/l]
Re^2: how to select which words have Y and W by Laurent_R (Canon) on Dec 26, 2013 at 12:12 UTC
Try this: `$ perl -e '@positive_int = grep {$_ >=0 } (12,-85,36,-10,75,-38); pri +nt "@positive_int"' 12 36 75` [download]	[reply] [d/l]
Re^2: how to select which words have Y and W by johngg (Canon) on Dec 26, 2013 at 12:13 UTC
Of course it's possible, just place a conditional in the grep. `$ perl -Mstrict -Mwarnings -E ' my @array = ( 12, -85, 36, -10, 75, -38 ); say qq{@array}; my @notNegatives = grep { $_ >= 0 } @array; say qq{@notNegatives};' 12 -85 36 -10 75 -38 12 36 75 $` [download] I hope this is helpful. Cheers, JohnGG	[reply] [d/l]
Re^2: how to select which words have Y and W by jethro (Monsignor) on Dec 26, 2013 at 12:17 UTC
Yes, grep works with arbitrary expressions. Just remember that every single value in the array is aliased to $_ inside the grep (i.e. $_ is a placeholder for the array value).	[reply]
Re^2: how to select which words have Y and W by rammohan (Acolyte) on Dec 26, 2013 at 12:31 UTC
Thanks to all it works for me..its silly point sorry for asking here.. from now on words i'll try my level best..Thank you for advices	[reply]