in reply to Data visualisation.
Hi,
what about something along these lines. Set A to coordinates (0,0) and B to coordinates (0, 633).
Say C has coordinates (x, y).
You have:
Solving this system of two equations is straight forward. (Hoping I did not goof the maths ;-) For the next points, one needs to be a bit more general and use the distances to A, B and C.sqrt (x² + y²) = 257 sqrt(x² + (633 - y)²) = 390
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