Re: issue with sprintf..

%d means signed integer, you are suffering from an overflow problem.

Since the floating point mantissa is much larger, %f for instanceš should mitigate the "problem" for some time.

  DB<109> $val=12143951645
 => "12143951645"

  DB<110> sprintf("%11.0f", $val);
 => "12143951645"
[download]

Only you can tell us how large your numerical ranges are...

Cheers Rolf

( addicted to the Perl Programming Language)

š) see also this post for discussion of string template %s

Comment on Re: issue with sprintf.. Download Code

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Re^2: issue with sprintf.. by sathya83aa (Acolyte) on Jan 09, 2014 at 10:35 UTC
Max length of the variable will be zero. Even the variable is of length 5, I want to prefix '0's to make the length 11. Thats my intention.	[reply]
Re^3: issue with sprintf.. by LanX (Saint) on Jan 09, 2014 at 10:38 UTC
so better use sprintf properly, put a leading 0 in the pattern after %. Your `s/ /0/` substitution is - politely said - less optimal. ;-) `DB<117> $val=12143 => 12143 DB<118> sprintf("%011.0f", $val); => "00000012143" DB<119> $val=12143951645 => "12143951645" DB<120> sprintf("%011.0f", $val); => "12143951645"` [download] please read the documentation for more details. =) Cheers Rolf ( addicted to the Perl Programming Language)	[reply] [d/l] [select]
Re^4: issue with sprintf.. by sathya83aa (Acolyte) on Jan 09, 2014 at 11:45 UTC
You mean to say I can remove that substitution s/ /0/ and simply use "sprintf("%011.0f", $val);" right?	[reply]
Re^3: issue with sprintf.. by hdb (Monsignor) on Jan 09, 2014 at 10:45 UTC
Or like this: `$Val2 = '0' x (11-length $Val2) . $Val2 if length $Val2 < 11;` [download] or this `$Val2 = substr "00000000000$Val2", -11;`	[reply] [d/l] [select]