in reply to Re^4: Problem with traversing a two dimensional array (to create an arrayref use [ ] )
in thread Problem with traversing a two dimensional array
gives you an array, on which you can use an index to find one element, for example:
No, a list is a list and not an array, perl lets you index a list, it doesn't make a list an array
On the other hand, this: does not give you an array, but an arrayref i.e. a single scalar. And an arrayref is what you need to oush onto an array if you want to build an AoA.
When you make an arrayref, what is that reference pointing to?
An array right?
so creating an arrayref creates an array (it make an array )
You probably know all that, I was only objecting to the fact that this was not made very clear in my humble opinion.
Well, if you wrote something like:
to clarify
to elaborate
to make more clear
to make more clear some details
to make more clear some subtle details
... some kind of words other than ... miss the main point
I probably wouldn't have responded
Correct corrections are welcome ; elaborations are usually welcome (if they don't go off topic from main thread too much)
wrong corrections not so much; they call the duty
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Re^6: Problem with traversing a two dimensional array (to create an arrayref use [ ] )
by no_slogan (Deacon) on Jan 17, 2014 at 01:48 UTC | |
by Anonymous Monk on Jan 17, 2014 at 02:01 UTC | |
by no_slogan (Deacon) on Jan 17, 2014 at 02:46 UTC | |
by Anonymous Monk on Jan 17, 2014 at 03:00 UTC |