in reply to Changing the numerical value from 0 to 1

You could match w/word boundaries:

for (@output5b) { s/\b0\b/1/ };

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Or you could match from start to end:

for (@output5b) { s/^0$/1/ }

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Or w/o a regex:

for (@output5b) { $_ = 1 if $_ == 0 }

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Edit: I believe that ww and kcott provided sufficient reasons below to keep only option #2.

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Re^2: Changing the numerical value from 0 to 1
by hellohello1 (Sexton) on Jan 21, 2014 at 02:21 UTC
    Word boundaries work !:) Thanks!
[reply]

      You're most welcome.

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