in reply to Does Perl have if(isset?

You should put your code in <code> tags. And without knowing a little Perl this is unlikely to get you far but this is roughly equivalent. I didn't use the if block because it is unperly (to me) when there is no real else.

use strict; # DO NOT LEAVE OUT. use warnings; # What did I just say?! use CGI ":standard"; my $comment; $comment = param("comment") if request_method() eq "POST"; # Note, $comment could be undefined/uninitialized here # but this is similar to your logical block.