Slowly figuring this out. I've got a full pathname in a variable that I'm trying to prepend some of the same information to. E:\triggers\...E:\triggers.

How do I just get the actual filename without all of the path information into a variable?

File::Basename basename

Finally got it working. Thanks all!!

use strict;
use warnings;
use File::Basename;

# Declare package names
my $work_file;
my $out_file;

my @files = <E:\\triggers\\1_MERGE_3326\\tests\\*.hl7>;

#$work_file = pop;  # If work_file comes from command line, uncomment
my $inPath = "E:\\triggers\\1_MERGE_3326\\pass";
my $outPath = "E:\\triggers\\1_MERGE_3326\\converted";

foreach $work_file (@files) {
print "$work_file\n";

open (WORK, "<$work_file") or die "Couldn't open $work_file."; # Open 
+the working file
my $outFile = basename($work_file);
print "$outFile\n";

open (OUT, ">$outPath\\$outFile") or die "Couldn't open $outPath\\$out
+File."; # open an output file

while (<WORK>) {
    chomp;
    $_ =~ tr/\000-\011\013\014\016-\037//d;
    print OUT map {"$_\n"} ($_);
} # end while

    close WORK;
    close $work_file;
} # end foreac
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