Re^3: Allocation of anonymous arrays

Oops, I meant:

  foreach my $ref (keys %fred)
  (
    $fred{$ref}->[2] = ++$i;
  )
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Re^4: Allocation of anonymous arrays by Anonymous Monk on Feb 07, 2014 at 11:49 UTC
sure, but you can write `for my $ref ( values %fred ){ $ref->[2] = ++$i; }` so that $ref is an actual ref :)	[reply] [d/l]