regex probs.

maddfisherman has asked for the wisdom of the Perl Monks concerning the following question:

why doesnt this work?

$xtemplate = "stuff i want to be in the first element of @template ***
+*filename.ext****";
my @template = $xtemplate =~ /(.*?)\*{4}filename.ext\*{4}/s;
why wont @template =("stuff i want to be in the first element of @temp
+late ")
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putting regex results into an array. (boo) by boo_radley (Parson) on Aug 23, 2001 at 23:13 UTC
your regex works (you can verify this by looking at the contents of $1), but you're not putting it into @template correctly. try this syntax, which forces the results of the regex into the proper context through the use of the outermost set of parens : `@template = ($xtemplate =~ /(.?)filename.ext\{4}/s);`	[reply] [d/l]
Re: putting regex results into an array. (boo) by apprentice (Scribe) on Aug 24, 2001 at 00:24 UTC
1 - Yes, the regex works fine, but so does all of the code. I.e., I see nothing wrong with the context, but maybe I'm not grokking something. I threw parentheses around the {4}filename.ext{4} portion of the regex and it was stored in the array properly, too. 2 - Perhaps maddfisherman was looking in $template1 instead of $template[0] ? apprentice	[reply]
Re: Re: putting regex results into an array. (boo) by apprentice (Scribe) on Aug 24, 2001 at 00:29 UTC
One thing I missed the first look, you need to escape the "@template" in the string like this "\@template" else your string, and hence the first element of @template will not have "@template". apprentice	[reply]