Re: String regex replacement

my %replacement = (
    500     => '000',
    988     => '000',
    1210    => '1000',
    1300    => '1000',
    2134    => '2000,
    2500    => '2000',
);

my $regex = join '|', keys %replacement;

$str =~ s/\b($regex)\b/$replacment{$1}/;
[download]

Untested, but it should work pretty much like this.

Perl 6 - the future is here, just unevenly distributed

Comment on Re: String regex replacement Download Code

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Re^2: String regex replacement by Skeeve (Parson) on Feb 24, 2014 at 12:02 UTC
Funny, exact, to the point -> ++! `s$$([},&%#}/&/]+}%&{});#$&&s&&$^X.($'^"%]=\&(\|?{%` `+`.+=%;.#_}\&"^"-+%*).}%:##%}={~=~:.")&e&&s""`$''`"e	[reply] [d/l] [select]
Re^2: String regex replacement by FloydATC (Deacon) on Feb 26, 2014 at 07:27 UTC
...now all we need is a script to generate that `%replacement` hash :o) -- FloydATC Time flies when you don't know what you're doing	[reply] [d/l]
Re^3: String regex replacement by hdb (Monsignor) on Feb 26, 2014 at 07:58 UTC
How about this? `use strict; use warnings; use Data::Dumper; my $post = "Hi, erm does anyone know how to do a string replacement th +at caters for all the following scenario? 500 changes to 000 or 0 988 + changes to 000 or 0 1210 changes to 1000 1300 changes to 1000 2134 c +hanges to 2000 2500 changes to 2000 Thanks in advance."; my %replacement = $post =~ /(\d+) changes to (\d+)/g; print Dumper \%replacement;` [download]	[reply] [d/l]