I'll repeat it.
Oops ... was that for *my* benefit ?
You're not telling me anything (here) that I don't already know.
However, looking back at my posts, at no time did I state that explicitly ... though I did make a couple of attempts to make it implicitly apparent - eg a reference to "trick" and the acknowledgement that I wasn't contradicting anything
you had said.
I did think it worthy of mention (but even that's probably debatable in hindsight) that in perl you can start with integers and operate on them in such a way that you derive a NaN - because you can't do that in (eg) C, afaik.
I also wondered whether that might have been something like the pathway that led
Laurent_R to the view that you could get a NaN from integer overflow.
But it seems
Laurent_R was alert to that aspect, anyway.
Cheers,
Rob