Re: perl -e hash assignment and range operator bug

Windows uses % as its environment variable token. You must double it to get a single one.

The code %a = (1,2,3,4); print %a is reduced to a because the commandline sees a = (1,2,3,4); print as the name of an environment variable.

_____________________________________________________
Jeff[japhy]Pinyan: Perl, regex, and perl hacker.
s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;

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(crazyinsomniac)Re^2: perl -e hash assignment and range operator bug by crazyinsomniac (Prior) on Aug 26, 2001 at 20:40 UTC
wow. It's been a while since I got bit by something like that. Been too much in bash lately. ___crazyinsomniac_______________________________________ `Disclaimer: Don't blame. It came from inside the void` `perl -e "$q=$_;map({chr unpack qq;H;,$_}split(q;;,qH*));print;$q/$q;"`	[reply]
Re: (crazyinsomniac)Re^2: perl -e hash assignment and range operator bug by japhy (Canon) on Aug 26, 2001 at 21:04 UTC
No, the problem is you're using Windows. _____________________________________________________ Jeff`[japhy]`Pinyan: Perl, regex, and perl hacker. `s++=END;++y(;-P)}y js++=;shajsj<++y(p-q)}?print:??;`	[reply]