Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:
Dear Monks, I present a bewildering consequence of postfix if() statements and variable assignment. Please help me find enlightenment!
A colleague's code both scopes a variable and tests another in postfix. I would expect this to trap the value inside the scope of the if() block, but for some reason I cannot see, it is persisting in style of a closure, and while the debugger reports undefined values in every iteration, print somehow finds meaning in the same scalar.
sub test{ my $i = shift; my $params = shift; my $test = $params->{test} if (exists $params->{test}); print "test after hash assignment:\t\t$test\n"; $test = $i unless (defined $test); print "i = $i test after defaulting to i:\t$test\n"; } for my $i (3..5){ &test($i) }
If I scope the test properly, everything works as I expect, but with this in-line scoping, it seems to be both defined and not. Note that $params is never set.
test1 after hash assignment: i = 3 test1 after defaulting to i: 3 test1 after hash assignment: 3 i = 4 test1 after defaulting to i: 3 test1 after hash assignment: 3 i = 5 test1 after defaulting to i: 3
Please help me to understand the execution order of that postfixed if line.
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Re: Weird scoping/ secret closure
by kcott (Archbishop) on Mar 28, 2014 at 19:15 UTC |