Re: Subarray in a hash: Can't use string ("STRING") as a HASH ref while "strict refs" in use

Round parentheses ( ... ) don't create a reference. Instead, use { ... } to create a hash reference:

my @array_of_hashes;

for (my $i=1; $i<=10; $i++) {
    $array_of_hashes[$i] = {
        stuff => 'stuffy',
        goes => 'gooey',
        here => "more $i"
    };

    $array_of_hashes[$i]{sub_data}[6] = "seven";
}
[download]

Update: In your original code, assignment to a hash value introduced a scalar context. In scalar context, the list in parentheses returned its last member, "more $i". You later tried to use this value as a hash reference.

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Re^2: Subarray in a hash: Can't use string ("STRING") as a HASH ref while "strict refs" in use by GeoJunkie (Initiate) on Apr 08, 2014 at 13:48 UTC
That did it! Is this just because it's a hash within an array? Normally, when defining a hash (as %hashname), you use round parentheses - at least that's what the Perl Cookbook says. Thanks!	[reply]
Re^3: Subarray in a hash: Can't use string ("STRING") as a HASH ref while "strict refs" in use by choroba (Cardinal) on Apr 08, 2014 at 13:51 UTC
`( )` are used for assignments to arrays and hashes. `[ ]` are used for array references, `{ }` are used for hash references. You are not assigning a hash, you are assigning a hash reference here. Updated. لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l] [select]
Re^4: Subarray in a hash: Can't use string ("STRING") as a HASH ref while "strict refs" in use by shawnhcorey (Friar) on Apr 08, 2014 at 14:22 UTC
No, ( ) is used for lists. Lists are converted into arrays by assignment. Also, lists are converted into hashes by assignment. Example: note the addition of the ``undef`` to make the hash work properly. `#!/usr/bin/env perl use strict; use warnings; use feature qw( :all ); # -------------------------------------- # Modules use Data::Dumper; # Make Data::Dumper pretty $Data::Dumper::Sortkeys = 1; $Data::Dumper::Indent = 1; # Set maximum depth for Data::Dumper, zero means unlimited local $Data::Dumper::Maxdepth = 0; # -------------------------------------- my @a = my %h = ( 1, 2, 3 ); say Dumper \@a; say Dumper \%h;` [download]	[reply] [d/l]
Re^3: Subarray in a hash: Can't use string ("STRING") as a HASH ref while "strict refs" in use by andal (Hermit) on Apr 08, 2014 at 13:52 UTC
Compare `%hash = (key1 => 'val1', key2 => 'val2'); $hash = {key1 => 'val1', key2 => 'val2'};` [download] The first one defines hash, the second defines reference to hash, which is scalar.	[reply] [d/l]