in reply to substitution in regular expression
You've placed code (push(@dic,$1);) inside the replacement part of the regular expression. Each three-letter code will be replaced by the string "push(@dic,$1);" instead of the code being executed, and because of that the string will never get shorter. Even though you could get the code to execute by adding the /e modifier on the regex, it still wouldn't do what you want (since the replacement value would be the return value of the push call), and so it's better to just move that code outside the regular expression.
Since you're matching three letters with your regular expression, and you want to replace those with the last two of those three letters, it's easier to just write it that way:
while(length($line)>2){ $line =~ s/([A-Z]([A-Z]{2}))/$2/; push(@dic, $1); }
I'm sure other monks will have (TI)MTOWTDI and more elegant solutions, but the above gets what you want with only a few changes.
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Re^2: substitution in regular experssion
by aeqr (Novice) on Apr 23, 2014 at 20:04 UTC | |
by AnomalousMonk (Archbishop) on Apr 23, 2014 at 20:13 UTC | |
by Anonymous Monk on Apr 23, 2014 at 20:14 UTC | |
by aeqr (Novice) on Apr 23, 2014 at 20:21 UTC | |
by AnomalousMonk (Archbishop) on Apr 23, 2014 at 20:34 UTC | |
by aeqr (Novice) on Apr 23, 2014 at 20:41 UTC | |
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by Anonymous Monk on Apr 23, 2014 at 20:30 UTC |