If all the files of interest are in one directory, and they all match a simple file-name pattern, and you just want to print the name of the largest file, here's one easy way to do that in Perl:
#!/usr/bin/perl
use strict;
use warnings;
my $path = "/tmp/dir1";
my %filesize = map { $_ => -s } <$path/d1*>;
my @sorted = sort { $filesize{$b} <=> $filesize{$a} } keys %files;
printf "Largest file: %s (%d bytes)\n", $sorted[0], $filesize{$sorted[
+0]};
Of course, I expect it would be better to have the path and file-name pattern of interest be a command line argument (or a sensible default, like all files in the current working directory), because hard-coding this in the script is bothersome. So I'd rather do it like this:
#!/usr/bin/perl
use strict;
use warnings;
my $glob_pattern = shift || './*';
my %files;
for ( glob( $glob_pattern )) {
$files{$_} = -s _ if ( -e );
}
if ( scalar keys %files == 0 ) {
warn "No files matched $glob_pattern\nUsage: $0 [path/name*]\n";
exit(1);
}
my @sorted = sort { $files{$b} <=> $files{$a} } keys %files;
printf( "Largest file that matches %s is %s (%d bytes)\n",
$glob_pattern, $sorted[0], $files{$sorted[0]} );
Now, in that case, when I run the script, I have to put the command-line argument in quotes, because otherwise, the shell will do the glob expansion, and my script will only see the first file name that matches the glob. In other words, if the script is called "show-biggest", the command line would have to be:
show-biggest '/tmp/dir1/d1*' # note the single quotes
# or:
show-biggest /tmp/dir1/d1\* # note the backslash escape for "*"
BTW, in trying this out, I learned that there is a subtle difference between this:
my @files = <something>;
and this:
my $glob = "something";
my @files = glob( $glob );
In the first approach, if "something" doesn't match anything, @files will be empty, but in the second approach, it will have one element, which is the string that was passed to the glob() function. The difference goes away if the value of $glob contains any wild-card characters (* or ? or square brackets) - I haven't checked, but I'll bet this is documented behavior... That's why I added a test for file existence (-e) in my second version of the script above.
I also learned that glob( $glob_pattern ) does the right thing, where <$glob_pattern> doesn't. (Perl treats the latter as an unopened file handle.) | [reply] [d/l] [select] |
You could use the core File::Find module and the stat function to scan a directory looking for the file taking up most disk blocks (512 bytes on many file systems though not all). Running the following code in my "Downloads" directory finds that a large CentOS ISO is the guilty culprit.
$ perl -MFile::Find -Mstrict -Mwarnings -E '
my %largest = ( name => q{}, size => 0 );
find( sub {
my $blocks = ( stat )[ 12 ];
do {
$largest{ name } = $File::Find::name;
$largest{ size } = $blocks;
} if $blocks > $largest{ size };
}, q{.}
);
say qq{$largest{ name } - $largest{ size } blocks};'
CentOS-5.10-x86_64-bin-DVD-1of2.iso - 9125976 blocks
$
I hope this is helpful.
Update: Substituted $File::Find::name for $_ to store the full path rather than just the file name.
| [reply] [d/l] [select] |
Your subject says that you want to use awk, which your code already does, and it works for me. You haven't indicated what the problem is?
Although you could just use the code you have, I'm guessing your question is how to do this in Perl.
Piece 1: List files with glob (there are other ways, such as readdir or Path::Tiny, but glob is good for simple tasks), e.g. glob('/tmp/dir1/d1*')
Piece 2: Get the size of a file with -s, e.g. -s $filename
Piece 3: Using an array of arrays to hold the filenames and sizes (see also perlreftut)
Piece 4: Sort numerically with sort, e.g. sort {$b<=>$a} @filesizes
Putting it all together:
my @filenames = glob '/tmp/dir1/d1*';
my @files_and_sizes;
for my $filename (@filenames) {
my $filesize = -s $filename;
push @files_and_sizes, [$filename, $filesize];
}
use Data::Dumper; # just for demo & debugging
print Dumper \@files_and_sizes; # just for demo & debugging
@files_and_sizes = sort { $$b[1] <=> $$a[1] } @files_and_sizes;
print Dumper \@files_and_sizes; # just for demo & debugging
my $var1 = $files_and_sizes[0][0];
print $var1;
This could even be dramatically shortened into a one-liner, esp. if you replace the for with map. There are also several other ways to do this, e.g. with modules. | [reply] [d/l] [select] |
Check and see if File::Util is available to you. I believe it will provide you with what you want if it is available. You can find out by running instmodsh. Hope that gives you a start...
Update
!/usr/bin/perl
use strict;
use warnings;
use File::Util;
my($f) = File::Util->new();
sub filesize {
my ( $selfdir, $subdirs, $files, $depth ) = @_;
print "$_ " . ( -s $_ ) . "\n" for sort { (-s $a) <=> (-s $b)
+} @$files;
}
$f->list_dir( '/tmp/dir1' => { recurse => 0, callback => \&filesize, p
+attern=>'\.pl$' } );
Update_2Forgot to mention that this code is right from the POD for the File::Util module. It is not mine!
...the majority is always wrong, and always the last to know about it...Insanity: Doing the same thing over and over again and expecting different results...
| [reply] [d/l] |
use Path::Tiny qw/ path /;
my @all_files = path( $dir )->realpath->children();
my @done = map { $$_[1] }
sort { $$a[0] <=> $$b[0] }
map { [ $_->stat->mtime, $_ ] }
grep m{d2[^\\/]+$}, @all_files;
my @dtwo = map { $$_[1] }
sort { $$a[0] <=> $$b[0] }
map { [ $_->stat->mtime, $_ ] }
grep m{d1[^\\/]+$}, @all_files;
| [reply] [d/l] |
Thanks all for the great info. You guys are amazing! I really expected to get shot down and told to do more newb research, but you all really helped! Thanks! | [reply] |