in reply to dereferencing use module
This is my general approach when I need to do something similar, in this case, a poor man's Module::Pluggable system:
# NOTE! This is just a snippet from a larger work shown only to illust +rate the principle use strict; use warnings use Cwd (); use Try::Tiny; # used to find the location of THIS module. assumes that all plug-ins # will be under a directory named after this module (without the '.pm' +) sub _basename_dir { my $class = shift; # In this case, we want to always use THIS package's name, not a s +ub-class my $package = __PACKAGE__; $package =~ s/::/\//g; my $packpath = $INC{ join( '.', $package, 'pm' ) }; $packpath =~ s/\.pm$//; my $realpath = Cwd::realpath($packpath); return $realpath; } # be sure to get the method in THIS package, not a sub-class my $basedir = __PACKAGE__->_basename_dir(); my $pdir = "$basedir/Plugin"; opendir( my $dh, $pdir)or die "Can not open $pdir"; my @plugins = grep { /\.pm$/ && -f "$basedir/Plugin/$_" } readdir($dh) +; closedir( $dh ) or die "Can not close $pdir"; for my $plugin ( @plugins ) { my $ppkg = try { my $package = __PACKAGE__; # gotta change from '::' to '/' so require is happy. $package =~ s/::/\//g; my $ppath = join( '/', $package, 'Plugin', $plugin); require $ppath; # and now we change back to normal '::' without the .pm to use + as a class name. $plugin =~ s{(?:\.pm)$}{}; my $pname = join( '::', __PACKAGE__, 'Plugin', $plugin ); return ($pname->isa( __PACKAGE__ ) && $pname->_enabled) ? $pna +me : undef ; } catch { warn "Invalid plugin: $plugin\n$_\n"; return; } or next; $ppkg->register(); }
There are probably better or cleaner ways to do this (this is Perl, after all) but this has been a very stable approach for me.
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