Re^4: array of hash

I don't want to build. I already build %currHash and then, want to assign the whole %currHash to the 3rd array element of %curr. Then, I will change the value of the keys of the hash which is the 3rd element of array of %curr but I don't want that %currHash gets changed

If I do such assignment, how come that the value of the CD doesn't exist when assigning %currHash or %tmp?

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Re^5: array of hash by choroba (Cardinal) on May 27, 2014 at 12:42 UTC
You have to change the way you build the structure, because it's the source of the problem. Please read all the comments and linked pages again to understand. `push @currArr, %currHash;` [download] This line does not insert a hash into an array. It flattens the hash to a list to be inserted. Use Data::Dumper to visualize the resulting structures. What structure do you exactly want to build? If you want to create a copy of a shallow hash, use `push @currArr, { %currHash };` [download] To create a deep copy, see Clone or Storable. لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l] [select]

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Re^5: array of hash
by choroba (Cardinal) on May 27, 2014 at 12:42 UTC

push @currArr, %currHash;
[download]

This line does not insert a hash into an array. It flattens the hash to a list to be inserted. Use Data::Dumper to visualize the resulting structures. What structure do you exactly want to build? If you want to create a copy of a shallow hash, use

push @currArr, { %currHash };
[download]

To create a deep copy, see Clone or Storable.

لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ

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