each function

adriang has asked for the wisdom of the Perl Monks concerning the following question:

Hi, Why the second while function don't work

my %weekday=(
        1 => "Monday",
        2 => "Tuesday",
        3 => "Wednesday",
        4 => "Thursday",
        5 => "Friday",
        6 => "Saturday",
        7 => "Sunday",
);



while ( (my @all )=each(%weekday) ) {
    say "@all";
}

while ( each(%weekday) ) {
    say;
}
[download]

Thanks in advance, Adrian

Update: I figure out how the each function is working: "Every time the each function is called, it grabs an element out of the hash and puts them ..." Shame me for the question Adrian

Comment on each function Download Code

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Re: each function by tobyink (Canon) on Jun 03, 2014 at 17:27 UTC
There are very good reasons to avoid using `each` entirely. `use Moops; class Cow :rw { has name => (default => 'Ermintrude') }; say Cow->new->name`	[reply] [d/l]
Re^2: each function by adriang (Sexton) on Jun 04, 2014 at 17:28 UTC
Thanks, it help me alot.	[reply]
Re: each function by choroba (Cardinal) on Jun 03, 2014 at 13:42 UTC
What do you mean by "don't work"? say without a parameter prints $_ (and $\), but neither while nor each assign to $_, so you are just getting a bunch of empty lines, one for each key of the hash. لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply]
Re^2: each function by RonW (Parson) on Jun 03, 2014 at 23:08 UTC
Elaborating: `each` returns a key/value pair, so you need to: `while (my ($k,$v) = each %hash)` [download] Though in a scalar context, `each` returns just the key, but I think `keys` is more readable: `for (keys %hash)` [download]	[reply] [d/l] [select]
Re: each function by AnomalousMonk (Archbishop) on Jun 03, 2014 at 19:39 UTC
And double shame and triple mortification upon you for deleting the original content of your OP and substituting something completely different — at least twice! Please see How (Not) To Ask A Question, Posting on PerlMonks, and especially How do I change/delete my post?. (Not that, given the tone of your post(s), you'll actually bother to make any effort, but one lives in hope...)	[reply]
Re^2: each function by adriang (Sexton) on Jun 04, 2014 at 17:26 UTC
Sorry for "deleting the original content", it was by mistake, I didn't know how to add a reply.	[reply]
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