czah7 has asked for the wisdom of the Perl Monks concerning the following question:
echo hello1 hello2 hello3|awk '{ print $1 }' and it prints "hello1"
In a script I need to do a similar thing, but the data is inside a variable.For example: echo $variable |awk '{ print $1 }'
I've tried several variations, I know I'm missing something very simple...$time = print $error|print $F[0]; or $time = system(echo $error) | system( awk '{print $1}'); or $time = print $error | system(awk '{ print $1 }');
None work. So to make it simple.$time should then = 2014-06-04T15:24:21-05:00#!/usr/bin/perl $error = '2014-06-04T15:24:21-05:00 syslog_dp [0x80e00099][ftp][error] + secure-backup(FBB): trans(5487)'; $time = print $error|print $F[0];
|
|---|
| Replies are listed 'Best First'. | |
|---|---|
|
Re: Simple awk question
by no_slogan (Deacon) on Jun 05, 2014 at 17:05 UTC | |
by czah7 (Initiate) on Jun 05, 2014 at 18:39 UTC | |
by czah7 (Initiate) on Jun 05, 2014 at 18:51 UTC | |
by jeffa (Bishop) on Jun 05, 2014 at 19:16 UTC | |
|
Re: Simple awk question
by Bloodnok (Vicar) on Jun 05, 2014 at 17:26 UTC | |
by LanX (Saint) on Jun 05, 2014 at 18:03 UTC | |
|
Re: Simple awk question
by LanX (Saint) on Jun 05, 2014 at 17:08 UTC | |
by RonW (Parson) on Jun 05, 2014 at 17:38 UTC | |
|
Re: Simple awk question
by GotToBTru (Prior) on Jun 05, 2014 at 18:13 UTC | |
by czah7 (Initiate) on Jun 05, 2014 at 18:35 UTC | |
by fishmonger (Chaplain) on Jun 05, 2014 at 19:02 UTC | |
by czah7 (Initiate) on Jun 05, 2014 at 19:29 UTC | |
by GotToBTru (Prior) on Jun 05, 2014 at 20:15 UTC | |
|