Re: at continue, last

I suppose there is more then one (disguised) goto otherwise nesting two if should do and is easily understood.

But no matter how many exit-points you have, the entry-point is always the same. So why don't you decrement there after the first if ?

Cheers Rolf

(addicted to the Perl Programming Language)

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Re^2: at continue, last by Anonymous Monk on Jun 06, 2014 at 17:41 UTC
`$loop` is used in the conditional, so if I decremented it first, I'd have to add one to it everywhere it is being used.	[reply] [d/l]
Re^3: at continue, last by LanX (Saint) on Jun 06, 2014 at 17:55 UTC
> $loop is used in the conditional, so if I decremented it first,... Unclear. None of your examples have `$loop` in the conditional and I suggested decrementing it after not before ! Please explain what's different here `if ( $condition1 ) { ... unless( $condition2 ) { ... } --$loop; # common exit point }` [download] Cheers Rolf (addicted to the Perl Programming Language)	[reply] [d/l] [select]
Re^4: at continue, last by djerius (Beadle) on Jun 06, 2014 at 18:28 UTC
Sorry, my reply was clearer in my head then in my written words I meant to write that if I decremented it as the first statement in the if clause, I'd have to increment later on. The point of the examples wasn't the decrement, but to examine the ways of finding a single path to cleanup code from a conditional. In particular, I'm trying to avoid the nested if/else/unless clauses.	[reply]
Re^5: at continue, last by LanX (Saint) on Jun 06, 2014 at 18:35 UTC
Re^6: at continue, last by djerius (Beadle) on Jun 06, 2014 at 18:43 UTC
Re^3: at continue, last by djerius (Beadle) on Jun 06, 2014 at 17:44 UTC
Whoops. Forgot to log in. The above comment is mine.	[reply]