in reply to Re: Strange int() result
in thread Strange int() result

It is no use in simply removing the dot. Probably you mean $amount =~ s/\..+//? int() is faster.

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Re^3: Strange int() result
by Laurent_R (Canon) on Jun 18, 2014 at 20:18 UTC
    How so? The OP's problem comes from the use of int function on a number calculated as 35784.45 * 100 and turning out to be very very slightly smaller than 3578445. It seems to me you probably read too quickly the OP. Example under the debugger:
    DB<10> $amount = 35784.45; DB<11> $amount =~ s/\.//; DB<12> print $amount; 3578445
      Very interesting test! I could not understand at first why multiplying with an even integer factor would introduce rounding errors. So it seemed, but when I went one step back and ignored the multiplication I saw: the value itself is not expressible as a fixedpoint binary number.

      So there are two ways to look at it (numerically and as a string):

      $ perl -wE '$x=35784.45; printf "%.15f\n%s", $x, $x;' 35784.449999999997090 35784.45

      Since now I always assumed the string representation were made from the numerical representation thus giving the same output. That was obviously wrong.

      Update:

      A second counter test

      $ perl -wE '$x=35784.449999999997090; printf "%.15f\n%s", $x, $x;' 35784.449999999997090 35784.45
      reveals: the string representation always uses some rounding.
        Another test under the debugger to give you food for thought:
        DB<13> printf "%d", 35784.45 * 100; 3578444 DB<14> printf "%s", 35784.45 * 100 3578445
        But the real question was addressed earlier by davido: where is the 35784.45 piece of data coming from? If it is read in a text file or from a text-format network, then using regexes or printf "%s", ... is not only right, but is probably the best solution. If it comes from a previous calculation or from binary data, then it may be slightly more complicated, details would be needed about its original format.
      Thanks, got the point. Shame on me.