tbone654 has asked for the wisdom of the Perl Monks concerning the following question:
I am looking for a "smooth" way to modify the code I'm simulating below... I read in a file "line-by-line" to an array and split on newline, leaving just the value of the line without the \n ... So I can create a delimited line of several items... first example
Where I get in trouble is where a line read in is blank, which shifts everything to the left in the output (notice the rogue ; at the end) because splitting on the newline leaves an empty entry... second example
I can check for an empty line and put a space in there which works, but it's just not sexy... third example
$ perl -e 'BEGIN{@words = ("one\n","two\n","three\n","four\n","five\n" +,"six\n",)} $a=0;printf("%s;%s;%s;%s;%s;%s\n",(split/\n/,@words[$a]), +(split/\n/,@words[$a+1]),(split/\n/,@words[$a+2]),(split/\n/,@words[$ +a+3]),(split/\n/,@words[$a+4]),(split/\n/,@words[$a+5]) );' one;two;three;four;five;six $ perl -e 'BEGIN{@words = ("one\n","two\n","three\n","\n","five\n","si +x\n",)} $a=0;printf("%s;%s;%s;%s;%s;%s\n",(split/\n/,@words[$a]),(spl +it/\n/,@words[$a+1]),(split/\n/,@words[$a+2]),(split/\n/,@words[$a+3] +),(split/\n/,@words[$a+4]),(split/\n/,@words[$a+5]) );' one;two;three;five;six; perl -e 'BEGIN{@words = ("one\n","two\n","three\n"," \n","five\n","six +\n",)} $a=0;printf("%s;%s;%s;%s;%s;%s\n",(split/\n/,@words[$a]),(spli +t/\n/,@words[$a+1]),(split/\n/,@words[$a+2]),(split/\n/,@words[$a+3]) +,(split/\n/,@words[$a+4]),(split/\n/,@words[$a+5]) );' one;two;three; ;five;six
I've been messing with this for 2 days now, and I'm wondering if anyone has a different way of thinking to share?
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Re: split on newline
by ikegami (Patriarch) on Sep 12, 2014 at 19:06 UTC | |
by tbone654 (Beadle) on Sep 12, 2014 at 20:02 UTC | |
by ikegami (Patriarch) on Sep 13, 2014 at 00:29 UTC | |
by AnomalousMonk (Archbishop) on Sep 12, 2014 at 20:30 UTC | |
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Re: split on newline
by Laurent_R (Canon) on Sep 12, 2014 at 21:32 UTC | |
by johngg (Canon) on Sep 12, 2014 at 22:24 UTC |