Rodster001 has asked for the wisdom of the Perl Monks concerning the following question:

Greetings! I am using IO::Compress::Zip but I cannot get the syntax quite right for what I am trying to do. Here is some pseudo code:

use IO::Compress::Zip qw(zip $ZipError);

my $zip = new IO::Compress::Zip \*STDOUT 
  or print STDERR "IO::Compress::Zip failed: $ZipError\n";

foreach my $file (@files) {

 ... do some stuff to the file

 ... now add file to the archive

} 

$zip->close;

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My problem: Using this the OO way I am not quite sure how to define the filename AND the contents of the file on each loop thus producing a stream to STDOUT with multiple files.

UPDATE

I ended up using Archive::Zip::SimpleZip. This seems to work good and does in fact stream the zip file from the server as it is being processed.


## when using '-', Stream is set to 1
my $z = new Archive::Zip::SimpleZip '-', 
  or print STDERR "Cannot create zip file: $SimpleZipError\n";

foreach my $file (@files) {

 ... do some stuff to the file

 my $fh = $z->openMember(Name => "<filename.ext>");
 print $fh <stuff>;
 close($fh);

} 

$z->close;

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Replies are listed 'Best First'.
Re: Multi file stream with IO::Compress::Zip
by NetWallah (Canon) on Sep 17, 2014 at 05:03 UTC
    I havent used this interface, but it looks like the syntax you need is : 
     # Possibly, need to set binmode...
$zip->newStream(name=>"SomeFileName.txt" );
# in a loop .. write data using:
$zip->write $data, $length, $offset;
# Then finally
$zip->close; # Or do newStream for some other file name..

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            "You're only given one little spark of madness. You mustn't lose it."         - Robin Williams

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[d/l]
      What I couldn't figure out is how to specify a new (change of) filename. But see my update above, I went with a different module and it does what I need.
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        If a streamed Zip file with multiple members is what you need then Archive::Zip::SimpleZip is probably the best way to go.

        I see in your code you've used '-' to force streaming. You can explicitly request streaming to a file/buffer by specifying the Stream option, as shown below. If writing to STDOUT is what you need, then you don't need to explicitly set it. 

        ## Explicitly ask for Stream is set to 1
my $z = new Archive::Zip::SimpleZip "somefile.zip, Stream => 1 
  or print STDERR "Cannot create zip file: $SimpleZipError\n";

        [download]

        FYI - I wrote Archive::Zip::SimpleZip because the interface I provided in IO::Compress::Zip to create a Zip file with multiple members is not the easiest to use. Archive::Zip::SimpleZip is just a wrapper around IO::Compress::Zip to make this use-case as easy as possible.

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[d/l]
Re: Multi file stream with IO::Compress::Zip
by Rozman (Initiate) on Sep 22, 2017 at 06:00 UTC

    This is what I created and works for me. When user opening some URL on my page I am creating ZIP archive on the fly and sending it to user.

    If change "-" to "file.zip" it will save archive into your hosting/server (and don't need print "content type").

       use IO::Compress::Zip qw(:all);

   my @files = ('example.gif', 'example1.png', 'example2.jpg', 'exampl
+e3.avi', 'example4.mov');

   my $path = "/home/********/**********";

   print "Content-Type:application/zip\n";
   print "Content-Disposition: attachment; filename=\"filename.zip\"\n
+\n";

   my $z;

   foreach my $file (@files) {
      if ($z) {
         $z->newStream(Name => $file, Method => ZIP_CM_STORE);
      } else {
         $z = new IO::Compress::Zip "-", Name => $file, Method => ZIP_
+CM_STORE;
      }

      open(FILE, "<", "$path/$file");
      binmode FILE;

      my ($buf, $data, $n);

      while (($n = read FILE,$data, 1024) != 0) {
         $z->print($data);
      }

      close(FILE);
   }

   $z->close;

   exit;

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[d/l]

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