Re^2: Subroutine evaluated as boolean (update: hash-slice)

> So the problem is that it's evaluating ADDRESS instead of the list itself?

Yes that's the effect if the scalar comma operator.

Just copy the list to a temporary @array to be returned.

Or return a literal construct like @{[L,I,S,T]}

Or best use a hash slice

return @$_{VALUE,NAME,ADDRESS} if ...

Cheers Rolf

_{(addicted to the Perl Programming Language and ☆☆☆☆ :)}

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Re^3: Subroutine evaluated as boolean by Anonymous Monk on Oct 13, 2014 at 01:07 UTC
In fact, `return @$_{'VALUE','ADDRESS'}` has the same problem as my original code. But `return @{[@$_{'VALUE','ADDRESS'}]}` works great, if it is a little confusing to a beginner like me.	[reply] [d/l] [select]
Re^4: Subroutine evaluated as boolean (central exit point) by LanX (Saint) on Oct 13, 2014 at 01:14 UTC
> `return @$_{'VALUE','ADDRESS'}` has the same problem as my original code yeah sorry, I just testedš ... ...it's a bit counterintuitive because of the leading @ ... :-/ > `@{[@$_{'VALUE','ADDRESS'}]}` works great, better don't combine both techniques, readability is more important! you could easily do something like `my @ret=(); for ( @$table ) { next unless $_->{VALUE} eq $wanted; @ret = @$_{VALUE, ADDRESS} } return @ret;` [download] To get a central exit point. update > if it is a little confusing to a beginner like me. the way context is propagated into subs is always confusing, that's why this was changed in Perl6's design! Cheers Rolf _{(addicted to the Perl Programming Language and ☆☆☆☆ :)} š) `DB<116> $_={a=>1,b=>2,c=>3,d=>0} => { a => 1, b => 2, c => 3, d => 0 } DB<117> sub tst { @$_{a,d} } DB<118> tst() => (1, 0) DB<119> scalar tst() => 0` [download]	[reply] [d/l] [select]