in reply to Re^4: parser bug handling 'do ($foo)->{bar}' ?
in thread parser bug handling 'do ($foo)->{bar}' ?
I do understand. I think too that it would be more intuitive for do EXPR; to be parsed as eval EXPR; but I'll sleep better for having an idea of where the difference comes from :).
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Re^6: parser bug handling 'do ($foo)->{bar}' ?
by LanX (Saint) on Oct 14, 2014 at 16:30 UTC | |
by LanX (Saint) on Oct 14, 2014 at 17:07 UTC | |
by ysth (Canon) on Oct 14, 2014 at 17:20 UTC |