in reply to count down with while loop
Probably quicker to jump in increments of $integer.
$ perl -Mstrict -Mwarnings -E ' my $lower = 100; my $upper = 200; my $int = 15; my $start = int( $upper / $int ) * $int; while ( $start >= $lower ) { say $start; $start -= $int; }' 195 180 165 150 135 120 105 $
I hope this is helpful.
Cheers,
JohnGG
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Re^2: count down with while loop
by rshoe (Novice) on Oct 23, 2014 at 16:47 UTC |