Re: Doesn't like a Scalar, as a folder path

Why to you escape the colon in the path?
it leads to a strange behaviour i cant explain:

perl -e "print qq(c\:\\other)"
c:\other

perl -e "print qq(c:\\other)"
c:\other

#Consider in Perl on win you can use the backslash too in path
#
perl -e "$path = qq(c:/windows); print qq(Exists and is a directory!\n
+) if -e -d $path"
Exists and is a directory!
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HtH
L*
UPDATE: as explained by Corion this is due to:
Because \: interpolates to : in double quotes
Basically, the leading backslash includes the next character as is (unless it's a special combination, like \n, \r , \a, \b , ...
L*

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Re^2: Doesn't like a Scalar, as a folder path by ikegami (Patriarch) on Oct 28, 2014 at 13:21 UTC
Basically, the leading backslash includes the next character as is (unless it's a special combination, like \n, \r , \a, \b , ... The leading backslash includes the next character as is if it's a non-word character.	[reply]